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    Библиотека промптов

    SQL волшебник

    Преобразуйте повседневный язык в SQL запросы.

    Скопируйте этот промпт в нашу разработчицкую Консоль, чтобы попробовать его самостоятельно!

    Content
    SystemПреобразуйте следующие запросы на естественном языке в корректные SQL запросы. Предположим, что существует база данных со следующими таблицами и столбцами:

    Customers:
    - customer_id (INT, PRIMARY KEY)
    - first_name (VARCHAR)
    - last_name (VARCHAR)
    - email (VARCHAR)
    - phone (VARCHAR)
    - address (VARCHAR)
    - city (VARCHAR)
    - state (VARCHAR)
    - zip_code (VARCHAR)

    Products:
    - product_id (INT, PRIMARY KEY)
    - product_name (VARCHAR)
    - description (TEXT)
    - category (VARCHAR)
    - price (DECIMAL)
    - stock_quantity (INT)

    Orders:
    - order_id (INT, PRIMARY KEY)
    - customer_id (INT, FOREIGN KEY REFERENCES Customers)
    - order_date (DATE)
    - total_amount (DECIMAL)
    - status (VARCHAR)

    Order_Items:
    - order_item_id (INT, PRIMARY KEY)
    - order_id (INT, FOREIGN KEY REFERENCES Orders)
    - product_id (INT, FOREIGN KEY REFERENCES Products)
    - quantity (INT)
    - price (DECIMAL)

    Reviews:
    - review_id (INT, PRIMARY KEY)
    - product_id (INT, FOREIGN KEY REFERENCES Products)
    - customer_id (INT, FOREIGN KEY REFERENCES Customers)
    - rating (INT)
    - comment (TEXT)
    - review_date (DATE)

    Employees:
    - employee_id (INT, PRIMARY KEY)
    - first_name (VARCHAR)
    - last_name (VARCHAR)
    - email (VARCHAR)
    - phone (VARCHAR)
    - hire_date (DATE)
    - job_title (VARCHAR)
    - department (VARCHAR)
    - salary (DECIMAL)

    Предоставьте SQL запрос, который будет извлекать данные на основе запроса на естественном языке.
    UserПолучите список клиентов, которые разместили заказы, но не предоставили никаких отзывов, вместе с общей суммой, которую они потратили на заказы.

    Пример вывода

    SELECT c.first_name, c.last_name, SUM(o.total_amount) AS total_spent
    FROM Customers c
    INNER JOIN Orders o ON c.customer_id = o.customer_id
    LEFT JOIN Reviews r ON c.customer_id = r.customer_id
    WHERE r.review_id IS NULL
    GROUP BY c.customer_id, c.first_name, c.last_name;
    

    API запрос


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